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以前做过一个C语言版五子棋：Ｃ语言＋二维数组＋非递归实现五子棋游戏

现在做一个Java语言版五子棋，规则如下：

1､白子为O;

2､黑子为@；

3､白子先手；

4､格子占满时为平局；

5､四个方向上有连续五个子为胜利；

6､如果选择0 3表示选的第1行与第4列；

废话不多说，直接上代码：

import java.util.Scanner;/*** 命令行版五子棋* 规则：* 1､白子为O;* 2､黑子为@；* 3､白子先手；* 4､格子占满时为平局；* 5､四个方向上有连续五个子为胜利；* 6､如果选择0 3表示选的第1行与第4列；*/
public class WuZiQi {public static final int N = 16;public static void main(String[] args) {Scanner sc = new Scanner(System.in);char[][] GAME = new char[N][N];int count = 0;    //轮换落子计算int m, n; //白家int x, y; //黑家int res = 0;wzq_init(GAME);wzq_show(GAME);while (true) {//当棋盘格子被下满了时if (N * N == count) {System.out.println("棋盘已经下满了，平局!");sc.close();return;}if (0 == count % 2) {System.out.print("请白家落子（例如0 3或1 3）：");m = sc.nextInt();n = sc.nextInt();while (m < 0 || m > N - 1 || n < 0 || n > N - 1) {System.out.print("输入的坐标超出范围，请重新输入：");m = sc.nextInt();n = sc.nextInt();}while ('+' != GAME[m][n]) {System.out.print("此处已经落过子，请重新落子：");m = sc.nextInt();n = sc.nextInt();}GAME[m][n] = 'O';res = wzq_play(m, n, GAME);if (1 == res) {wzq_show(GAME);System.out.println("程序结束");sc.close();return;}} else {System.out.print("请黑家落子（例如0 3或1 3）：");x = sc.nextInt();y = sc.nextInt();while (x < 0 || x > N - 1 || y < 0 || y > N - 1) {System.out.print("输入的坐标超出范围，请重新输入：");x = sc.nextInt();y = sc.nextInt();}while ('+' != GAME[x][y]) {System.out.print("此处已经落过子，请重新落子：");x = sc.nextInt();y = sc.nextInt();}GAME[x][y] = '@';res = wzq_play(x, y, GAME);if (1 == res) {wzq_show(GAME);System.out.println("程序结束");sc.close();return;}}count++;wzq_show(GAME);}}//显示五子棋棋盘public static void wzq_show(char[][] GAME) {System.out.println("五子棋棋盘如下：");for (int i = 0; i < N; i++) {for (int j = 0; j < N; j++) {System.out.print(GAME[i][j]);}System.out.println();}}//初始化五子棋棋盘public static void wzq_init(char[][] GAME) {for (int i = 0; i < N; i++) {for (int j = 0; j < N; j++) {GAME[i][j] = '+';}}}//游戏是否胜利的运算,一旦有人胜利则返回1public static int wzq_play(int a, int b, char[][] GAME) {int i = 0, j = 0, k = 0;//方向-上的for (j = b - 4; j < b + 4; j++) {if (j < 0 || j > N - 1) {continue;}for (i = 0; i < 5; i++) {if (j + i < 0 || j + i > N - 1) {break;}if ('@' == GAME[a][j + i] || '+' == GAME[a][j + i]) {break;}if ('O' == GAME[a][j + i] && 4 == i) {System.out.println("\n恭喜你，白家－方向上获胜!");return 1;}}for (i = 0; i < 5; i++) {if (j + i < 0 || j + i > N - 1) {break;}if ('O' == GAME[a][j + i] || '+' == GAME[a][j + i]) {break;}if ('@' == GAME[a][j + i] && 4 == i) {System.out.println("\n恭喜你，黑家－方向上获胜!");return 1;}}}//方向|上的for (i = a - 4; i < a + 4; i++) {if (i < 0 || i > N - 1) {continue;}for (j = 0; j < 5; j++) {if (i + j < 0 || i + j > N - 1) {break;}if ('@' == GAME[i + j][b] || '+' == GAME[i + j][b]) {break;}if ('O' == GAME[i + j][b] && 4 == j) {System.out.println("\n恭喜你，白家｜方向上获胜!");return 1;}}for (j = 0; j < 5; j++) {if (i + j < 0 || i + j > N - 1) {break;}if ('O' == GAME[i + j][b] || '+' == GAME[i + j][b]) {break;}if ('@' == GAME[i + j][b] && 4 == j) {System.out.println("\n恭喜你，黑家｜方向上获胜!");return 1;}}}//方向\上的for (i = a - 4, j = b - 4; i < a + 4 && j < b + 4; i++, j++) {if (i < 0 || i > N - 1 || j < 0 || j > N - 1) {continue;}for (k = 0; k < 5; k++) {if (i + k < 0 || i + k > N - 1 || j + k < 0 || j + k > N - 1) {break;}if ('@' == GAME[i + k][j + k] || '+' == GAME[i + k][j + k]) {break;}if ('O' == GAME[i + k][j + k] && 4 == k) {System.out.println("\n恭喜你，白家＼方向上获胜!");return 1;}}for (k = 0; k < 5; k++) {if (i + k < 0 || i + k > N - 1 || j + k < 0 || j + k > N - 1) {break;}if ('O' == GAME[i + k][j + k] || '+' == GAME[i + k][j + k]) {break;}if ('@' == GAME[i + k][j + k] && 4 == k) {System.out.println("\n恭喜你，黑家＼方向上获胜!");return 1;}}}//方向/上的for (i = a + 4, j = b - 4; i > a - 4 && j < b + 4; i--, j++) {if (i < 0 || i > N - 1 || j < 0 || j > N - 1) {continue;}for (k = 0; k < 5; k++) {if (i - k < 0 || i - k > N - 1 || j + k < 0 || j + k > N - 1) {break;}if ('@' == GAME[i - k][j + k] || '+' == GAME[i - k][j + k]) {break;}if ('O' == GAME[i - k][j + k] && 4 == k) {System.out.println("\n恭喜你，白家/方向上获胜!");return 1;}}for (k = 0; k < 5; k++) {if (i - k < 0 || i - k > N - 1 || j + k < 0 || j + k > N - 1) {break;}if ('O' == GAME[i - k][j + k] || '+' == GAME[i - k][j + k]) {break;}if ('@' == GAME[i - k][j + k] && 4 == k) {System.out.println("\n恭喜你，黑家/方向上获胜!");return 1;}}}return 0;}
}

idea里面测试可以正常运行，游戏结果正常，运行环境：jdk1.8+win11。