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点击链接返回标题->基于非链式(数组)结点结构的二叉树的层序、先序、中序、后序输入创建以及层序、先序、中序、后序输出-CSDN博客
层序可谓是最简单的二叉树遍历了。。。。
代码很浅显易懂,相信你能明白的!
#include<iostream>
using namespace std;
typedef int datatype;
const int MAX = 8;
struct binTree {datatype tree[2 * MAX + 7];//该数组的最大容量必须超过最大结点数的两倍,用以存放空结点!int size;//当前有效结点个数
};void create_tree_seq(binTree* tree) {//按层序创建二叉树int x, i = 1;while (cin >> x) {//处理到无输入为止(返回-1,按Ctrl + z)//层序输入结点,并主观规定->输入-1代表该结点为空tree->tree[i++] = x;if (x != -1) tree->size++;}
}void travse_seq(binTree* tree) {//二叉树的层序遍历int len = tree->size, i = 1;while (len) {if (tree->tree[i] != -1) {//访问到的不是空结点就输出,并让len自减,len为0时所有有效结点均被输出printf("%d ", tree->tree[i++]);len--;}}
}
完整测试代码如下:
样例输入:
1 2 3 4 5 6 7 -1 -1 -1 -1 -1 -1 -1 -1
样例输出:
层序遍历结果——1 2 3 4 5 6 7
先序遍历结果——1 2 4 5 3 6 7
中序遍历结果——4 2 5 1 6 3 7
后序遍历结果——4 5 2 6 7 3 1
#include<iostream>
using namespace std;
typedef int datatype;
const int MAX = 8;
struct binTree {datatype tree[2 * MAX + 7];//该数组的最大容量必须超过最大结点数的两倍,用以存放空结点!int size;//当前有效结点个数
};void create_tree_seq(binTree* tree) {//按层序创建二叉树int x, i = 1;while (cin >> x) {//处理到无输入为止(返回-1,按Ctrl + z)//层序输入结点,并主观规定->输入-1代表该结点为空tree->tree[i++] = x;if (x != -1) tree->size++;}
}void travse_seq(binTree* tree) {//二叉树的层序遍历int len = tree->size, i = 1;while (len) {if (tree->tree[i] != -1) {//访问到的不是空结点就输出,并让len自减,len为0时所有有效结点均被输出printf("%d ", tree->tree[i++]);len--;}}
}
void travse_pre(binTree* tree, int i = 1) {//二叉树的先序遍历if (tree->tree[i] == -1) return;//访问到空结点,该递归路线需要返回//根,左,右printf("%d ", tree->tree[i]);travse_pre(tree, i * 2);travse_pre(tree, i * 2 + 1);
}
void travse_mid(binTree* tree, int i = 1) {//二叉树的中序遍历if (tree->tree[i] == -1) return;//左,根,右travse_mid(tree, i * 2);printf("%d ", tree->tree[i]);travse_mid(tree, i * 2 + 1);
}
void travse_nex(binTree* tree, int i = 1) {//二叉树的后序遍历if (tree->tree[i] == -1) return;//左,右,根travse_nex(tree, i * 2);travse_nex(tree, i * 2 + 1);printf("%d ", tree->tree[i]);
}
void test(binTree* tree) {create_tree_seq(tree);cout << "层序遍历结果——";travse_seq(tree);cout << endl;cout << "先序遍历结果——";travse_pre(tree);cout << endl;cout << "中序遍历结果——";travse_mid(tree);cout << endl;cout << "后序遍历结果——";travse_nex(tree);cout << endl;
}
int main() {binTree tree;tree.size = 0;memset(tree.tree, -1, sizeof(tree.tree));//初始化树的相关信息test(&tree);
}